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A balloon 150 meters from the observer is rising vertically at constant rate. After 1 minute the angle of elevation is 28 degrees and 29 minutes. What is the angle after 3 minutes?

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4 answers

  1. thanks big help

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  2. You're so !!!

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  3. tan(28deg59min)= h/150
    h= 83.0893 m/min

    @3 min
    tan(theta)= h(@3min)/150
    theta= arctan [(83.0893*3min)/150]
    theta= 58.9621 deg

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  4. To figure the height after 1 minute,

    h/150 = tan 28°29'

    Now, having h, you know that 3h is the altitude after 3 minutes. So, find the angle θ such that

    tanθ = 3h/150

    Or, in one step,

    θ = arctan(3*150*tan28°29')

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