1. JUGGLING NUMBERS
From old newspapers cut out digits 0 to 9 and stick them in a creative manner. Make sure the digits are not too small. Juggle the digits to make the numbers described below.
The challenge is you can use a digit only once in a number.
1) Make the smallest number using all the digits.
2) Make the greatest number using all the digits.
3) Make the greatest possible number that is greater than 8000 but less than 8500.
4) Make the smallest number that is greater than 4316.
5) Make the number which comes between 4999 and 5001.
6) Make the successor of 2090.
7) Make the predecessor of 8000.
so, did you do any of what was asked?
Calculate the sum of all possible two-digits numbers using the digits 3 and 4?
Make the smallest number that is greater than 4316
Solve this question
To solve these juggling numbers challenges, you will need the digits 0 to 9 cut out from old newspapers. Here's how you can solve each challenge:
1) Make the smallest number using all the digits.
- Arrange the digits in ascending order. The smallest number using all the digits is 0,123,456,789.
2) Make the greatest number using all the digits.
- Arrange the digits in descending order. The greatest number using all the digits is 9,876,543,210.
3) Make the greatest possible number that is greater than 8000 but less than 8500.
- Start with the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9.
- Place the digit 8 as the thousands place value.
- Place the digit 5 as the hundreds place value.
- Fill the remaining digits from highest to lowest in the tens and ones place, resulting in the number 8,745.
4) Make the smallest number that is greater than 4316.
- Start with the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9.
- Place 4 as the thousands place value to make the number greater than 4316.
- Arrange the remaining digits in ascending order, resulting in the number 4,567.
5) Make the number which comes between 4999 and 5001.
- Start with the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9.
- Place 5 as the thousands place value.
- Fill the remaining digits from highest to lowest in the hundreds, tens, and ones place, resulting in the number 5,000.
6) Make the successor of 2090.
- Start with the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9.
- Arrange them to form the number 2,090.
- Find the next number after 2,090, which is 2,091.
7) Make the predecessor of 8000.
- Start with the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9.
- Arrange them to form the number 8,000.
- Find the previous number before 8,000, which is 7,999.