Illustrate a scene with a full, cylindrical water tank outdoors during the daytime. The tank is metallic and 70cm in diameter, filled to the brim with clear, reflective water. Beneath it, one can see a small, steady stream of water leaking, forming a puddle on the ground. There's a floating marker inside the tank showing the water level drop by 20cm. The sky above is bright, underscoring the passing of time, with visible shift from morning to slightly past noon sun.

A cylindrical water tank is 70cm in diameter to begin with it is full of water a leak starts in the bottom so that it looses 10 litres every 1 hour how long will it take for the water level to fall by 20cm.

a 1-cm thick layer of water has a volume of π*35^2 cm^3 = 3.848 L

So, you want to know how long it takes to drain 20cm = 76.97L

76.97L ÷ 10L/hr ≈ 7.7 hr

So, this is it.

We are asked to determine how long it'd take for 20cm of water to be displaced.

We have r=35cm.
If we take a height of 1 cm, the volume of that would be
3.14 x 35^2 x 1 = 3,846.5cm^3.
3,846.5cm^3 = 3.85L (2 d.p)

For height of 20cm, the volume would be
3.14 x 35^2 x 20 = 76,930cm^3
76,930cm^3 = 76.93L

so, 10L lost in 1 hr, 76.93L will be lost in
76.93/10 = 7.693hrs.

Pls explain better 😕🙁

Please who understands this???

I didn't see the workings

Last explanation very explanatory.

Kudos

A cylindrical water tank is 70cm in diameter to begin with it is full of water a leak starts in the bottom so that it looses 10 litres every 1 hour how long will it take for the water level to fall by 20cm.

a 1-cm thick layer of water has a volume of π*35^2 cm^3 = 3.848 L

So, this is it.

Pls explain better 😕🙁

Please who understands this???

I didn't see the workings

Last explanation very explanatory.

Thanks for the explanation. it really helps a lot

Explain better

EXPLAIN BETTER

Working is not too explanative