A 230 kg steel crate is being pushed along a cement floor. The force of friction is 480 N to the left and the applied force is 1860 N to the right. What is the acceleration of the crate? (Hint: remember to find net force first)

a=6.00 m/s2
a=28.1 m/s2
a=8.10 m/s2
a=6.0 m/s2

6.0m/s^2

To find the acceleration of the crate, we need to calculate the net force acting on it. The net force is the vector sum of all the forces acting on an object.

In this case, we have two forces acting on the crate: the force of friction and the applied force. The force of friction is acting to the left with a magnitude of 480 N, and the applied force is acting to the right with a magnitude of 1860 N.

To find the net force, we subtract the force of friction from the applied force:

Net force = Applied force - Force of friction
Net force = 1860 N - 480 N
Net force = 1380 N (to the right)

Now that we have the net force, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration:

Net force = Mass × Acceleration

Rearranging the equation to solve for acceleration, we get:

Acceleration = Net force / Mass

Therefore, the acceleration of the crate is:

Acceleration = 1380 N / 230 kg
Acceleration = 6.00 m/s²

So the correct answer is a = 6.00 m/s².

net force is ... 1860 - 480

the acceleration is the net force divided by the mass

significant figures appear to be a factor (Hint: there are two)

A 230 kg steel crate is being pushed along a cement floor. The force of friction is 480 N to the left and the applied force is 1860 N to the right. What is the acceleration of the crate? (Hint: remember to find net force first)