How many ammonia liters of ammonia gas are produced when 85 grams of liquid nitrogen completely react?

N2 + 3H2 = 2NH3

you get twice the moles of ammonia.

moles N2=85/28
moles NH3=85/14

Now liters of ammonia gas depends on temp, and pressure.
At STP, it would be 85/14*22.4 liters

To find the number of liters of ammonia gas produced when 85 grams of liquid nitrogen react completely, we need to use stoichiometry.

First, we need to determine the molar mass of liquid nitrogen (N2) and ammonia (NH3). The molar mass of nitrogen (N2) is 28 g/mol, and the molar mass of ammonia (NH3) is 17 g/mol.

Next, we need to convert the given mass of liquid nitrogen (85 grams) to moles. We can do this by dividing the mass by the molar mass:

85 g / 28 g/mol = 3.04 mol

According to the balanced equation, 1 mol of nitrogen reacts to produce 2 mol of ammonia. So, we can use this ratio to calculate the number of moles of ammonia produced:

3.04 mol of N2 x (2 mol of NH3 / 1 mol of N2) = 6.08 mol of NH3

Now, we have the number of moles of ammonia produced. To convert this to liters, we need to use the ideal gas law equation, PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant (0.0821 L·atm/mol·K), and T is the temperature.

Assuming the reaction is carried out at standard temperature and pressure (STP), which is 0 degrees Celsius (273.15 K) and 1 atmosphere, we can substitute the values into the equation:

V = (nRT) / P
= (6.08 mol) x (0.0821 L·atm/mol·K) x (273.15 K) / (1 atm)
= 13.29 L

Therefore, approximately 13.29 liters of ammonia gas will be produced when 85 grams of liquid nitrogen completely react.