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EACH LETTER IN EACH ADDITION PROBLEM STANDS FOR A NUMBER BETWEEN 0 AND 9.NO TWO LETTERS STAND FOR THE SAME NUMBER IN EACH QUESTION. FIND THE VALUE FOR EACH LETTER.FOR EACH PROBLEM, USE THE NUMBERS IN THE BOX NEXT TO THE PROBLEM.

T E N (5,6,1,2,7)
+ O N
_________

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5 answers

  1. Something seems to be missing.

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  2. THOSE WERE THE INSTRUCTION(THIS IS THIRD GRADE MATH)

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  3. If you were not given letters for the answer, then just pick any values you want!

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  4. Answer=EGG

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  5. clearly, E=T+1 because of the carry. So, T is 1,5,6

    G is even (since it is N+N), so it is 2,6

    Now just a little trial and error yields

    671
    +51
    ------
    722

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