Pure acetic acid, known as glacial acetic acid, is a liquid with a density of 1.049 g/mL at 25°C. Calculate the molarity of a solution of acetic acid made by dissolving 35.00 mL of glacial acetic acid at 25°C in enough water to make 400.0 mL of solution.
Gms of HOAc = (35.0ml)(1.049g/ml) = 36.715gms HOAc
moles HOAc = (36.715 g)/(60.05 g/mol) = 0.6114 mole
Molarity = moles/Liters
= (0.6114-mole/0.400-L)
=1.53-Molar
First determine the M of the glacial acetic acid.
1000 mL x 1.049 g/mL x 1.00 x (1/molar mass acetic acid) = ?M
Ah, chemistry questions! Now you're speaking my language, or should I say, element language? Here's how we can calculate the molarity:
First, we need to find the number of moles of glacial acetic acid we have. To do that, we'll convert the volume from mL to liters and then multiply it by the density to find the mass.
35.00 mL x (1.049 g/mL) = 36.715 g
Next, we'll convert the mass to moles using the molar mass of acetic acid, which is approximately 60.05 g/mol:
36.715 g / 60.05 g/mol = 0.611 moles
Now, we have the moles of acetic acid. We just need to find the molarity by dividing the moles by the volume of the solution in liters:
Molarity = Moles / Volume
Volume = 400.0 mL / 1000 mL/L = 0.4 L
0.611 moles / 0.4 L = 1.53 M
So, the molarity of the acetic acid solution is approximately 1.53 M. And remember, always be careful with glacial acetic acid. It's glacially cool, but it can also be quite acetic!
To calculate the molarity of the solution, you need to first calculate the number of moles of acetic acid present in the solution.
Step 1: Calculate the number of moles of glacial acetic acid.
To do this, you need to convert the volume (in mL) of glacial acetic acid to liters, and then use the density of acetic acid to convert to grams.
First, convert the volume of glacial acetic acid to liters:
35.00 mL = 35.00 mL * (1 L / 1000 mL) = 0.035 L
Next, calculate the mass of glacial acetic acid using the density:
Mass = Density * Volume
Mass = 1.049 g/mL * 35.00 mL = 36.715 g
Step 2: Calculate the number of moles of acetic acid.
To do this, you need to use the molar mass of acetic acid, which is 60.052 g/mol.
Number of moles = Mass / Molar mass
Number of moles = 36.715 g / 60.052 g/mol = 0.6111 mol
Step 3: Calculate the molarity.
Molarity is defined as moles of solute divided by liters of solution.
Molarity = Number of moles / Volume of solution in liters
Molarity = 0.6111 mol / (400.0 mL * (1 L / 1000 mL)) = 0.1528 mol/L
Therefore, the molarity of the acetic acid solution is 0.1528 mol/L.
To calculate the molarity of a solution, you need to know the number of moles of solute and the volume of the solution in liters.
First, let's calculate the number of moles of glacial acetic acid. We can use the equation:
moles = mass / molar mass
The molar mass of acetic acid, CH3COOH, is:
(12.01 g/mol * 2) + (1.008 g/mol * 4) + (16.00 g/mol) = 60.05 g/mol
The mass of glacial acetic acid can be calculated using its density:
mass = density * volume
For the given volume of glacial acetic acid (35.00 mL) and its density (1.049 g/mL), we have:
mass = 1.049 g/mL * 35.00 mL = 36.715 g
Now we can calculate the number of moles:
moles = 36.715 g / 60.05 g/mol ≈ 0.611 moles
Next, we need to find the volume of the solution in liters. The given volume is 400.0 mL, so we convert it to liters:
volume = 400.0 mL * (1 L / 1000 mL) = 0.400 L
Finally, we can calculate the molarity using the formula:
molarity = moles / volume
molarity = 0.611 moles / 0.400 L ≈ 1.53 M
Therefore, the molarity of the acetic acid solution is approximately 1.53 M when 35.00 mL of glacial acetic acid is dissolved in enough water to make a 400.0 mL solution.