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Convert the Cartesian coordinate (-1,2) to polar coordinates, 0≤θ<2π

I know r is sqrt(5) but how would I find theta between 0 and 2pi?
Thanks in advance!

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2 answers
  1. you know that the point is in quad II and
    tanØ = 2/-1

    I know that for tanØ= +2, Ø = appr 1.107
    so our angle in II is Ø = π-1.107 = 2.0344

    so it has to be (5, 2.0344) if you use the form (r,Ø)

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  2. I see thanks for the help! I forgot to put my calculator on radian mode and got a totally different answer!

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