A photon has a frequency of 7.3 × 10–17 Hz. Planck’s constant is 6.63 × 10–34 J•s.
The energy of the photon, to the nearest tenths place, is
× 10–50 J.
E=h*f=7.3E-17*6.63E-34=4.8E-50J
I guess that is your q
I am trying to figure out how to get the answer when you has a photon frequency of 7.3* 10-17Hz and planck's constant is 6.63*10-34J.s the energy of the photon, to the nearest tenths place, is - *10-50J
To find the energy of a photon, we can use the equation E = hf, where E is the energy, h is Planck's constant, and f is the frequency of the photon.
Given:
Frequency = 7.3 × 10^(-17) Hz
Planck’s constant (h) = 6.63 × 10^(-34) J•s
Using the formula E = hf, we can substitute the given values:
E = (6.63 × 10^(-34) J•s) * (7.3 × 10^(-17) Hz)
Now, let's multiply the numbers:
E = (6.63 * 7.3) * (10^(-34) J•s * 10^(-17) Hz)
When multiplying numbers in scientific notation, we need to multiply the coefficient values and add the exponents to get the final answer:
E = 48.249 * 10^(-34 - 17) J•s•Hz
E = 48.249 * 10^(-51) J•s•Hz
To find the energy to the nearest tenth place, we need to round the coefficient value to one decimal place:
E ≈ 48.2 * 10^(-51) J•s•Hz
So, the energy of the photon, to the nearest tenth place, is approximately 4.82 × 10^(-50) J.
E=h*f=7.3E-17*6.63E-34=4.8E-50J
I guess that is your question