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We can find the solutions of

sin x = 0.6
algebraically. (Round your answers to two decimal places.)

(a) First we find the solutions in the interval
[0, 2π).
We get one such solution by taking
sin−1
to get
x = ________
(smaller value).

The other solution in this interval is
x =
(larger value).


(b) We find all solutions by adding multiples of
to the solutions in
[0, 2π).
The solutions are
x =
.
(Enter your answers in the form θ + 2πk, 0 ≤ θ < 2π. Enter your answers as a comma-separated list.)

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1 answer
  1. 0.64, 2.50 (π-0.64)

    I'm not sure what is meant by part (b), but in the given domain, the only two answers are 0.64 and 2.50 (2 decimal places)

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