were are doing free fall right now in the class

the question is

A worker drops a wrench form the top of a tower 80.0m tall. What is the velocity when the wrench strikes the ground?

I know that the change of distance 80.0m

I know aceleration of free fall is -9.81m/s^2

but I don't think that I have enough information to find the velocity final because I don't know the velocity initial I'm completly lost

Help Me

Fhghu

Assume that he just dropped the wrench and the initial velocity is 0

-80 = -(1/2) 9.81 t^2
t = sqrt (160/9.81) = 4.04 seconds before crash
so
V = 0 - 9.81 t = -39.6 m/s

Oh no! It seems like you're in a bit of a wrenching situation. Don't worry, I'm here to help you out with some gravity-defying humor!

Well, if you drop a wrench from the top of a tower, it's definitely not going to land softly like a feather. It will come crashing down with the force of gravity.

To solve this problem, we can use the basic equation of motion:

v^2 = u^2 + 2as

Where:
v is the final velocity (what we're looking for),
u is the initial velocity (which in this case is 0 as the wrench is dropped),
a is the acceleration due to gravity (-9.81 m/s^2), and
s is the distance traveled (which is 80.0m in this case).

Since we know the initial velocity is 0, we can simplify the equation to:

v^2 = 2as

Now you can plug in the values:

v^2 = 2 * (-9.81 m/s^2) * 80.0m

Now solve for v:

v^2 = -1568.8 m^2/s^2

Uh-oh, that negative sign means we're going to need imaginary numbers to calculate the velocity, and physics doesn't really play well with imaginary numbers.

So, it seems there's a bit of a flaw in the problem. We don't have enough information to calculate the final velocity unless we know the initial velocity. But don't worry, gravity isn't going to let that wrench hover in the air forever. It will definitely come crashing down with some speed!

I hope this clarified things for you, even though we couldn't find the exact velocity. If you have any more physics puzzlers or need a good chuckle, feel free to ask!

To find the final velocity of the wrench when it strikes the ground, you can use kinematic equations. The key equation you can use in this case is the equation for free fall:

Vf^2 = Vi^2 + 2ad

Where:
- Vf is the final velocity (which we're trying to find)
- Vi is the initial velocity (which we don't know in this case)
- a is the acceleration due to gravity (-9.81m/s^2)
- d is the displacement or change in distance (80.0m)

Since the wrench is initially dropped from rest (no initial velocity), the initial velocity can be considered as 0. Thus, the equation becomes:

Vf^2 = 0^2 + 2(-9.81m/s^2)(80.0m)

Simplifying this equation:

Vf^2 = -2(9.81m/s^2)(80.0m)

Vf^2 = -1569.6m^2/s^2

Now, to find the final velocity Vf, we can take the square root of both sides of the equation:

Vf = sqrt(-1569.6m^2/s^2)

However, since the square root of a negative value is not defined in the realm of real numbers, we need to consider that the wrench will have a downward velocity when it strikes the ground. Hence, the final velocity should have a negative value.

Thus, the final velocity Vf is approximately -39.6m/s. Note the negative sign, which indicates that the wrench is falling down towards the ground.