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Create a visually appealing image that represents a woman and her son depicted in different stages of their lives, symbolizing the passing of time. The woman, with noticeable signs of maturity, is in her prime years while her son is in his youthful years, showcasing a stark contrast in their ages. Have them perhaps sitting on a park bench, with a tree behind them showing the passing of seasons. The tree has blossoms blooming on one side and leaves falling on the other side, highlighting the progression of time. Please ensure the image contains no text.

a woman is 4 times as old as the son. in 5 years time she will be 3 times as old as the son. how old is the woman?....need an answer now

age of son ---- x

age of woman --- 4x

5 years from now:
son : x+5
woman : 4x+5

4x+5 = 3(x+5)

solve for x

10

Thanks Reiny, you almost got the answere, since x=10 and the woman is four times. The answere is =40

Her son= x

Woman= 4x
Five years time
Her son=x+5
Woman = 4x+5
4x+5=3(x+5)
4x+5=3x+15
4x_3x=15_5
X=10 years ago

Son=x

Woman=4x
In 5yrs Time woman=4x+5
Son in 5yrs=x+5
4x+5=3(x+5)
4x+5=3x+15
4x-3x=15-5
X=10

I no no 🙄

4x+5=3(x+5)

4x+5=3x+15
Collect like terms
4x-3x=15-5
Therefore, x=10

Here are some test questions for you:

1. Simplify: 4x + 2y - 3x + 5y
2. Solve for x: 3x + 6 = 21
3. Factorize: x² + 4x + 4
4. Find the distance between (-3, 4) and (5, -2)
5. Evaluate: (1/2)^3 - (1/2)^2 + (1/2)^1

Let me know if you need any help with these questions.

1) x+7y

2)x=5
3) (x+2)²
5) 3/8

Good job! However, for question 4, the distance formula is:

d = √[(x2 - x1)^2 + (y2 - y1)^2]

Using the given points (-3, 4) and (5, -2), we can plug the values into the formula to get:

d = √[(5 - (-3))^2 + (-2 - 4)^2]
d = √[8^2 + (-6)^2]
d = √[64 + 36]
d = √100
d = 10

Therefore, the distance between the two points is 10 units.