A group charters 3 identical buses and occupies 4/5 of the seats. After 1/4 of the passengers leae, the remaining passangers use only 2 of the busses what fraction of the seats on the two buses are now occupied?

assume number of seats on all buses is 3x and in one bus x. how do you solve??

The number of passengers after 1/4 leave is

(3/4)(4/5)3x = 9x/5 = 1.8 x

The capacity of two buses is 2x

The fraction of seats occupied is
1.8x/2x = 9/10

Though i solved it differently, but the result is same.๐Ÿ˜

To solve this problem, let's break it down step by step:

Step 1: Find the total number of seats on each bus.
Given that the number of seats on all the buses is 3x and on one bus is x, we can conclude that each bus has x seats.

Step 2: Calculate the total number of passengers initially.
Since the group occupies 4/5 of the seats, it means that 4/5 of the seats are filled with passengers. Let's represent the total number of passengers initially as P.

Therefore, the number of passengers initially is 4/5 of the total number of seats:
P = (4/5) * 3x
P = (12/5) * x

Step 3: Determine the number of passengers who leave.
After 1/4 of the passengers leave, the remaining fraction of passengers is 3/4 of the initial number of passengers, which can be calculated as:
Remaining passengers = (3/4) * (12/5) * x
Remaining passengers = (9/10) * x

Step 4: Calculate the number of passengers on the two buses.
Since all the passengers will now fit into 2 of the buses, we divide the remaining passengers equally between the two buses. Therefore, the number of passengers on each of the two buses is:
(9/10) * x / 2
(9/20) * x

Step 5: Determine the fraction of seats occupied on the two buses.
Since each bus has x seats, and there are two buses, the total number of seats on the two buses is 2x.
To find the fraction of seats occupied, we divide the number of passengers on the two buses by the total number of seats:
Fraction of seats occupied = [(9/20) * x] / 2x
Fraction of seats occupied = 9/40

Therefore, the fraction of seats occupied on the two buses after 1/4 of the passengers leave is 9/40.

To solve this problem, let's break it down step by step:

1. Begin by assuming that each bus has the same number of seats, denoted by "x." Since there are three identical buses, the total number of seats on all three buses can be represented as 3x.

2. It is given that initially, 4/5 of the seats were occupied. So, the number of occupied seats when all three buses were filled can be calculated as (4/5) * 3x = (12/5)x.

3. After 1/4 of the passengers leave, the remaining passengers use only 2 of the buses. This means that only 2x seats are being utilized by the remaining passengers.

4. To find the fraction of seats now occupied on the two buses, divide the number of occupied seats (2x) by the total number of seats on the two buses. Since each bus has x seats, the total number of seats on the two buses is 2x. Therefore, the fraction of seats now occupied can be calculated as (2x)/(2x) = 1/1 = 1.

Hence, after 1/4 of the passengers leave, the fraction of seats occupied on the two buses is 1 or 100%.