DRAW LOCUS OF POINT SO THAT IT IS EQUIDISTANT FROM BC & CA . ... constructed such that none of these triangles overlaps triangle ABC. a) Draw a triangle ABC and then sketch ... 16) AB = 3.2cm BC = 8.4cm The area of the triangle ABC is 10cm². ... CONSTRUCT ANGLE ABC WHERE AB=AC=10cm AND BC=9cm

if BC and CA are lines, then the locus of points equidistant from both lines is the bisector of the angle between them.

If24 is division 2

To construct an angle ABC where AB = AC = 10cm and BC = 9cm, follow these steps:

1. Draw a line segment AB and mark its length as 10cm.
2. From point A, use a compass to draw an arc with a radius of 9cm. Label the intersection points of this arc with line segment AB as D and E.
3. Place the compass on point D and draw an arc inside the triangle.
4. Without changing the compass width, place the compass on point E and draw another arc that intersects the arc from step 3.
5. Label the point of intersection between the two arcs as F.
6. Connect points A and F with a straight line segment.
7. Draw a perpendicular bisector of line segment AF. This bisector intersects line segment AF at point C.
8. Label point C.
9. Draw a line segment BC to complete the triangle ABC.

Now, you have a triangle ABC where AB = AC = 10cm and BC = 9cm.

To construct the locus of points equidistant from BC and CA, follow these steps:

1. Draw triangle ABC with sides AB = 10 cm, BC = 9 cm, and CA = 10 cm. Label the vertices A, B, and C.

2. Take the compass and set it to a radius equal to the distance between points B and C (8.4 cm). Place the compass needle on point B and draw an arc intersecting the line BC.

3. Without changing the compass width, place the compass needle on point C and draw another arc intersecting the line CA.

4. Now, take the compass and set it to a radius equal to the distance between points C and A (10 cm). Place the compass needle on point C and draw an arc intersecting the line AC.

5. Without changing the compass width, place the compass needle on point A and draw another arc intersecting the line AB.

6. You will notice that the two arcs intersect at two points. These two points are equidistant from sides BC and CA. They represent the locus of points that are equidistant from BC and CA.

7. Connect these two points with a line segment. This line segment is the locus of points equidistant from BC and CA.

To construct angle ABC with AB = AC = 10 cm and BC = 9 cm, follow these steps:

1. Draw a line segment BC with a length of 9 cm.

2. Place the compass needle on point B and draw an arc with a radius of 10 cm.

3. Without changing the compass width, place the compass needle on point C and draw another arc intersecting the previous arc.

4. Label the intersection point between the two arcs as point A.

5. Connect points A, B, and C to form triangle ABC.

Now you have successfully constructed angle ABC with AB = AC = 10 cm and BC = 9 cm.