2H2+O2=2H2O
H=-484KJ
Which answer best describes the transfer of heat that occurs when 1.41 mol of H2 reacts with 0.671 mol of O2?
341 kJ released
484 kJ released
341 kJ absorbed
484 kJ absorbed
325 kJ released
325 kJ absorbed
325 kJ released
¡A¡C
Well, well, well! It seems we have a chemistry question here, my friend! Time to put on our lab goggles and get silly with some jokes!
So, the given reaction is 2H2 + O2 = 2H2O, and it is stated that H = -484 KJ. Now, let's take a closer look at those answer choices.
If we calculate the number of moles of H2 that react, we get 1.41 mol. For O2, we have 0.671 mol. The reaction stoichiometry tells us that for every 2 moles of H2, we need 1 mole of O2. Hmm, interesting!
Now, let's think, which answer describes the transfer of heat? Ah, yes! It's like a game of hot potato, but with KJ instead. Is heat released or absorbed during this reaction?
Since the given H value is negative, that means heat is released! So, 484 KJ is released, just like a funny punchline that brings laughter to everyone!
Therefore, the correct answer would be: 484 kJ released.
Keep up the great work, and remember, science can have a sense of humor too!
To determine the transfer of heat that occurs during the given reaction, you can use the concept of enthalpy change (∆H) and the stoichiometry of the reaction. The given information implies that the reaction is exothermic since the enthalpy change (∆H) is negative (-484 KJ), indicating that heat is released during the reaction.
Now, let's examine the stoichiometry of the reaction: 2H2 + O2 → 2H2O.
According to the balanced equation, the mole ratio between H2 and H2O is 2:2, which means that for every 2 moles of H2 that react, 2 moles of H2O are produced.
Given that 1.41 moles of H2 and 0.671 moles of O2 react, it is clear that O2 is in excess since there is not enough O2 to react with all of the H2.
Using the stoichiometry, we can calculate the amount of heat transferred for the complete reaction:
2 moles of H2 releases -484 KJ.
Since there is an excess of H2, only 1.41 moles of H2 will react with the available 0.671 moles of O2.
To find the amount of heat transferred for this reaction, we can set up a proportion using the given information:
(1.41 mol H2 / 2 mol H2) * -484 KJ = -338.16 KJ
Therefore, the transfer of heat that occurs when 1.41 mol of H2 reacts with 0.671 mol of O2 is approximately -338.16 KJ. In other words, 338.16 kJ of heat is released.
Among the given options, the closest answer is 325 kJ released.