An engine absorbs 2000J of heat from a hot reservoir and expels 750J to a cold reservoir during each operating cycle. What is the power output of the engine if each cycle lasts for 0.5 seconds?
To find the power output of the engine, we need to determine the amount of work done by the engine in each operating cycle.
The work done by the engine is equal to the difference between the heat absorbed from the hot reservoir and the heat expelled to the cold reservoir.
In this case, the engine absorbs 2000J of heat and expels 750J of heat. Therefore, the work done by the engine is:
Work = Heat absorbed - Heat expelled
= 2000J - 750J
= 1250J.
Now, we need to find the power output. Power is defined as the amount of work done per unit time. We are given that each cycle lasts for 0.5 seconds. Therefore, the power output of the engine is:
Power = Work done / Time taken
= 1250J / 0.5s
= 2500W.
Hence, the power output of the engine is 2500 watts.
P = W/t
So what's the net work you're getting out of the system?