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What is the heat in Joules required to raise the temperature of 25 grams of water from 0 °C to 100 °C? What is the heat in calories? Knowing that 4.18 J = 1 calorie and C= 4.18 J/g·°C

M=25g C=4.18 J/g Tf=100 Ti=0
Q=25g x4.18j/g (100-0)
Q=25x4.18x(100)
Q=104.5(100)
Q=10,450

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2 answers

  1. M=25g C=4.18 J/g Tf=100 Ti=0
    Q=25g x4.18j/g (100-0)
    Q=25x4.18x(100)
    Q=104.5(100)
    Q=10,450

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  2. M=25g C=4.18 J/g Tf=100 Ti=0
    Q=25g x4.18j/g (100-0)
    Q=25x4.18x(100)
    Q=104.5(100)
    Q=10,450

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩

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