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A 2.50g bullet, traveling at a speed of 425m/s, strikes the wooden block of a ballistic pendulum. The block has a mass of 270g

(a) find the speed of the bullet/block combination immediately after the collision
(b) how high does the combination rise above its initial position?

(a) (bullet mass) x (bullet initial velocity) = (total mass) x (speed of bullet & block)
Solve for (speed of bullet & block)

(b) since kinetic energy of bullet & block = increase in potential energy at top of swing
g h = (1/2) (speed of bullet & block)^2

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2 answers

  1. A 2.50-g bullet, traveling at a speed of 425 m/s. strikes the wooden block of a ballistic pendulum, such as that in Figure 7.12. The block has a mass of 215 g. (a) Find the speed of the bullet/block combination immediately after the collision. (b) How high does the combination rise above its initial position?

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    2. 👎
    3. ℹ️
    4. 🚩
  2. 1209

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