write a balanced equation for the reaction that occurs when an aqueous solution of iron(II) chloride is mixed with an aqueous solution o potassium hydroxide.
Being as these are in an aqueous solution it brings to mind the pressence of ions.
Im not saying this is correct (it's only a guess) but the potassium could displace iron from the chloride producing Potassium chloride (simple reactivity series of metals) and Solid Iron. The hydroxide could possibly just gain another H to become water.
I don't know if this is the correct answer as i'm only doing my A levels but this is what i think would happen.
Hope you can work out the equation from that.
Bad guess.
FeCl2(aq) + 2KOH(aq) ==> Fe(OH)2(s) + 2KCl(aq)
Fe(OH)2 is insoluble in water solution.
The balanced equation for the reaction between iron(II) chloride (FeCl2) and potassium hydroxide (KOH) can be written as:
FeCl2 + 2KOH -> Fe(OH)2 + 2KCl
This equation shows that one mole of iron(II) chloride reacts with two moles of potassium hydroxide to form one mole of iron(II) hydroxide and two moles of potassium chloride.
To write a balanced equation for the reaction between iron(II) chloride and potassium hydroxide, we need to determine the chemical formulas of the products formed when these two compounds react.
First, let's write the chemical formulas for iron(II) chloride and potassium hydroxide:
- Iron(II) chloride has the chemical formula FeCl2
- Potassium hydroxide has the chemical formula KOH
Now, let's break down the reaction:
1. Write the reactants:
FeCl2 + KOH
2. Identify the products:
The reaction between iron(II) chloride and potassium hydroxide will yield iron(II) hydroxide (Fe(OH)2) and potassium chloride (KCl).
So, the balanced equation for the reaction is:
FeCl2 + 2KOH -> Fe(OH)2 + 2KCl
To balance the equation, we ensure that the number of atoms of each element is the same on both sides of the equation. In this balanced equation, we have two potassium atoms, two chlorine atoms, one iron atom, and four hydrogen and oxygen atoms on each side of the equation.