When the rubber band in a slingshot is stretched, it obeys Hooke's law. Suppose that the "spring constant" for the rubber band is k = 44.2 N/m. When the rubber band is pulled back with a force of 9.38 N, how far does it stretch?

To determine how far the rubber band stretches, we can use Hooke's law, which states that the force applied on a spring is directly proportional to the displacement of the spring.

Hooke's law equation: F = k * x

Where:
F is the force applied (9.38 N)
k is the spring constant (44.2 N/m)
x is the displacement or stretch of the rubber band (unknown)

Rearranging the equation to solve for x:
x = F / k

Substituting the given values:
x = 9.38 N / 44.2 N/m

Calculating:
x ≈ 0.212 meters

Therefore, the rubber band stretches approximately 0.212 meters.

To find the distance the rubber band stretches, we can use Hooke's law, which states that the force exerted by a spring is directly proportional to the extension or compression of the spring.

Hooke's law equation can be written as:
F = k * x

where F is the force applied, k is the spring constant, and x is the displacement or stretch of the rubber band.

In this case, we are given the spring constant, k = 44.2 N/m, and the force exerted, F = 9.38 N. We need to find the distance or stretch, x.

Rearranging the equation, we get:
x = F / k

Substituting the given values, we have:
x = 9.38 N / 44.2 N/m

Now, we can calculate the stretch of the rubber band:
x ≈ 0.2117 meters, or approximately 21.17 cm.

Therefore, when the rubber band is pulled back with a force of 9.38 N, it stretches approximately 0.2117 meters.

stretch=force/k=44.2/9.38 m

that is a long rubber band.