In a lottery game, a player picks 7 numbers from 1 to 45. How many different choices does the player have if order doesn't matter?
she is ronge because you cant add it to gether.
The number of ways to select 7 from 1 to 45
= C(45,7) = 45,379,620
(x3-2x2+x-6)divide by(x-3)
To find the number of different choices a player has in a lottery game where order doesn't matter, you can use the concept of combinations.
In this case, the player needs to select 7 numbers out of a total of 45 numbers.
The formula to calculate the number of combinations is:
nCr = n! / (r! * (n - r)!)
Where n is the total number of options available (in this case, 45) and r is the number of options to be chosen (in this case, 7). The exclamation mark (!) denotes the factorial function.
Applying the formula:
45C7 = 45! / (7! * (45 - 7)!)
Simplifying the expression:
45! = 45 * 44 * 43 * ... * 3 * 2 * 1
7! = 7 * 6 * 5 * 4 * 3 * 2 * 1
(45 - 7)! = 38!
Now, calculate each factorial:
45! = 45 * 44 * 43 * ... * 3 * 2 * 1 = 45,379,638,400
7! = 7 * 6 * 5 * 4 * 3 * 2 * 1 = 5,040
38! = 38 * 37 * 36 * ... * 3 * 2 * 1 = 523,022,617,466,601,111,760,007,224,100,074,291,200,000,000
Finally, substitute these values into the combination formula:
45C7 = 45,379,638,400 / (5,040 * 523,022,617,466,601,111,760,007,224,100,074,291,200,000,000)
Calculating this expression will give you the total number of different choices a player has.