A large swimming pool has a perimeter of 1,028 meters, this rectangular-shaped pool is 40 meters longer than 5 times its width. Find its dimensions.

width m
length m

Let's assume the width of the pool is represented by "W" meters.

According to the problem, the length of the pool is 40 meters longer than 5 times its width, which can be written as:

Length = 5W + 40

The perimeter of a rectangle is calculated by adding the lengths of all its sides. In this case, the perimeter is given as 1,028 meters, so:

Perimeter = 2(Length + Width)

Substituting the values we know:

1,028 = 2((5W + 40) + W)

Simplifying the equation:

1,028 = 12W + 80

Subtracting 80 from both sides:

1,028 - 80 = 12W

948 = 12W

Now, divide both sides by 12 to solve for W:

W = 948 / 12

W = 79

Therefore, the width of the pool is 79 meters.

Now, substitute this value back into the expression for the length:

Length = 5W + 40

Length = 5(79) + 40

Length = 395 + 40
Length = 435

So, the dimensions of the swimming pool are:

Width = 79 meters
Length = 435 meters

To find the dimensions of the swimming pool, we can set up a system of equations with the given information.

Let's assume that the width of the pool is "w" meters.
According to the problem, the length of the pool is 40 meters longer than 5 times its width. So, the length can be represented as: 5w + 40.

The perimeter of a rectangle is given by the formula: perimeter = 2(length + width).
Substituting the given values, we have:
1,028 = 2(5w + 40 + w)

Now, let's solve this equation to find the value of "w", which represents the width of the pool.

Expanding the equation, we have:
1,028 = 2(6w + 40)
1,028 = 12w + 80

Now, let's isolate "w" by subtracting 80 from both sides of the equation:
1,028 - 80 = 12w
948 = 12w

Finally, let's solve for "w" by dividing both sides of the equation by 12:
w = 948 / 12
w ≈ 79

So, the width of the swimming pool is approximately 79 meters.

To find the length of the pool, we can substitute this value back into the expression for the length:
length = 5w + 40
length = 5(79) + 40
length = 395 + 40
length = 435

Therefore, the dimensions of the swimming pool are approximately:
Width: 79 meters
Length: 435 meters

L = 5W + 40

2L + 2W = 1028

Substitute 5W+40 for L in the second equation and solve for W. Insert that value into the first equation to solve for L. Check by putting both values into the second equation.

Doesnt make sense