The area of a rectangular garden is given by the trinomial x^2+x-30. What are the possible dimensions of the rectangle? Use factoring.
A)(x-6) and (x-5)*
B)(x+6) and (x-5)
C)(x+6) and (x+5)
B)(x-6) and (x+5)
No, Evan, I thought we had ruled out C
Did you expand C before you decided?
for C: (x+6)(x+5)
= x^2 + 5x + 6x + 30
= x^2 + 11x + 30, not the given expression
for B:
(x+6)(x-5)
= x^2 - 5x + 6x - 30
= x^2 + x - 30 , the given!!
ohhh so its B @Reiny
Guys, its still correct! PogChamp is now illegal so pls dont call the cops on me
When I expand your choice of answer, I get
x^2 - 11x + 30, so clearly not the right answer.
you can tell from the -30, that the two constants must be of opposite sign, ruling out A and C
Try expanding the other two
cool indeed, "Jamal did it".
. cool
🙎🏾
To find the possible dimensions of the rectangle, we need to factor the trinomial x^2 + x - 30.
1. First, we look for two numbers that multiply together to give -30 and add up to 1 (the coefficient of the x term).
The numbers that satisfy this condition are -5 and 6. (Because -5 * 6 = -30 and -5 + 6 = 1)
2. Next, we rewrite the trinomial as a product of two binomials using these two numbers:
x^2 + x - 30 = (x - 5)(x + 6)
3. Now we have the factored form of the trinomial, and we can see that the possible dimensions of the rectangle are (x - 5) and (x + 6).
Therefore, the correct answer is A) (x - 6) and (x - 5).