Calculate the mass of copper (ii) sulphate which needs to be used to prepare 500cm³ of a 0.1M solution.

I assume you want to prepare 500 cc of the CuSO4. How many mols do you want? That's M x L = 0.1 x 0.500 = ?

Then convert to grams. g = mols x molar mass = ?

0.05

To calculate the mass of copper (II) sulfate required to prepare a 0.1M solution in a volume of 500 cm³, we need to use the formula:

Mass (g) = Molarity (mol/L) x Volume (L) x Molar Mass (g/mol).

First, we need to determine the molar mass of copper (II) sulfate (CuSO₄).

- Atomic mass of copper (Cu) = 63.55 g/mol.
- Atomic mass of sulfur (S) = 32.07 g/mol.
- Atomic mass of oxygen (O) = 16.00 g/mol.

Molar mass of CuSO₄ = (1 x Cu) + (1 x S) + (4 x O)
= (1 x 63.55 g/mol) + (1 x 32.07 g/mol) + (4 x 16.00 g/mol)
= 63.55 g/mol + 32.07 g/mol + 64.00 g/mol
= 159.62 g/mol.

Now, let's calculate the mass of copper (II) sulfate:

Mass (g) = 0.1 mol/L x 0.5 L x 159.62 g/mol
= 7.98 g.

Therefore, you would need approximately 7.98 grams of copper (II) sulfate to prepare a 0.1M solution in a volume of 500 cm³.

To calculate the mass of copper (II) sulfate required to prepare a 0.1M solution in a given volume, you need to know the molar mass of copper (II) sulfate and the desired concentration.

The molar mass of copper (II) sulfate (CuSO4) can be found using the atomic masses of copper (Cu), sulfur (S), and oxygen (O) from the periodic table.

The atomic mass of copper (Cu) is 63.55 g/mol.
The atomic mass of sulfur (S) is 32.06 g/mol.
The atomic mass of oxygen (O) is 16.00 g/mol.

To calculate the molar mass of copper (II) sulfate (CuSO4), you will add up the atomic masses of the individual elements in the compound:

Molar mass of CuSO4 = (1 * Cu) + (1 * S) + (4 * O)

= (1 * 63.55 g/mol) + (1 * 32.06 g/mol) + (4 * 16.00 g/mol)

= 63.55 g/mol + 32.06 g/mol + 64.00 g/mol

= 159.61 g/mol

Now that we know the molar mass of copper (II) sulfate is 159.61 g/mol, we can calculate the mass required to prepare a 0.1M solution.

Mass (g) = Molarity (M) * Volume (L) * Molar mass (g/mol)

First, convert the volume from cm³ to liters:

Volume (L) = 500 cm³ ÷ 1000 cm³/L

= 0.5 L

Now calculate the mass:

Mass (g) = 0.1 mol/L * 0.5 L * 159.61 g/mol

= 7.981 g

Therefore, you would need approximately 7.981 grams of copper (II) sulfate to prepare a 500 cm³ (0.5 L) solution with a concentration of 0.1M.