When aqueous solutions of chromium(III) bromide and potassium phosphate are combined, solid chromium(III) phosphate and a solution of potassium bromide are formed. The net ionic equation for this reaction is:

Well, chemistry can be quite a puzzle, can't it? Let me bring out my chemistry clown nose for this one!

Okay, so we have chromium(III) bromide and potassium phosphate doing their dance here. When they come together, solid chromium(III) phosphate and a solution of potassium bromide show up to steal the spotlight.

To write the net ionic equation, we need to strip away all the spectators and focus on the real performers. In this case, the main actors are the ions that really undergo a change.

So, let's imagine all the spectators have taken their seats and we're left with just the ions. We have chromium(III) ions from the chromium(III) bromide and phosphate ions from potassium phosphate.

In the reaction, the chromium(III) ions get cozy with the phosphate ions, and they form solid chromium(III) phosphate. Meanwhile, the bromide ions jump into the solution, creating a solution of potassium bromide.

The net ionic equation, my friend, is:

Cr³⁺ + 3PO₄³⁻ → CrPO₄(s)

That's the main act! Fancy, isn't it? So, imagine this equation as the grand finale of a chemistry show, where the chromium(III) and phosphate ions steal the spotlight, leaving the audience (the bromide and potassium ions) in awe.

I hope that cleared things up while bringing a smile to your face. If you have any more chemistry questions or if you need a dose of clown humor, don't hesitate to ask!

To determine the net ionic equation for the reaction between chromium(III) bromide and potassium phosphate, we need to write the balanced molecular equation first.

The balanced molecular equation is:
2 CrBr₃ + 3 K₃PO₄ → Cr₂(PO₄)₃ + 6 KBr

Next, we can break down the soluble ionic compounds into their respective ions. The solid chromium(III) phosphate does not break down since it is insoluble.

2 Cr³⁺ + 6 Br⁻ + 3 K⁺ + 3 PO₄³⁻ → Cr₂(PO₄)₃ + 6 K⁺ + 6 Br⁻

The ions that remain the same on both sides of the equation (spectator ions) can be eliminated to write the net ionic equation.

Net ionic equation:
2 Cr³⁺ + 3 PO₄³⁻ → Cr₂(PO₄)₃

To find the net ionic equation for this reaction, we first need to write the balanced chemical equation for the reaction.

The chemical formula for chromium(III) bromide is CrBr3, and the chemical formula for potassium phosphate is K3PO4. When these compounds react, they will form chromium(III) phosphate (CrPO4) and potassium bromide (KBr).

The balanced chemical equation for this reaction is:

3 CrBr3 + 2 K3PO4 → CrPO4 + 6 KBr

Next, we need to write the ionic equation by breaking up the reactants and products into their respective ions:

3 Cr3+ + 6 Br- + 6 K+ + 2 PO4 3- → CrPO4 + 6 K+ + 6 Br-

Now, we can cancel out the spectator ions (ions that appear on both sides of the equation) to get the net ionic equation:

3 Cr3+ + 2 PO4 3- → CrPO4

Therefore, the net ionic equation for the reaction between chromium(III) bromide and potassium phosphate is:

3 Cr3+ + 2 PO4 3- → CrPO4

When aqueous solutions of chromium(III) sulfate and sodium phosphate are combined, solid chromium(III) phosphate and a solution of sodium sulfate are formed. The net ionic equation for this reaction is:

Write the molecular equation and balance it.

CrBr3(aq) + K3PO4(aq) ==> CrPO4(s) + 3KBr(aq)

Separate into the complete ionic equation. It should be obvious that the aq solutions ionize and the solid is shows as the molecule since it doesn't dissolve.
Cr^3+(aq) + 3Br^-(aq) + 3K^+(aq) + PO4^3-(aq) ==> CrPO4(s) + 3K^+(aq) + 3Br^-(aq)

Now look and cancel those ions common to both sides. I see thed 3Br^- on left and right and 3 K^+ left and right. Mark those off. What is left is the net ionic equation.

Cr^3+(aq) + PO4^3-(aq) ==> CrPO4(s)