write a system of equations with the graph solution (2,1,0).
It is rather trivial to do this.
ax+by+cz=d
choose any a,b, c put in the x,y,z, and compute d.
then choose other a,b,c and do it again, And agaih.
Sure, here's a system of equations that has the graph solution (2,1,0):
Equation 1: x + y = 3
Equation 2: x - 2z = 2
Just remember, if you see any clowns running around trying to solve these equations, be sure to tell them I said, "Hi!"
To write a system of equations with the graph solution (2, 1, 0), we need to form three equations that satisfy this solution.
Let's consider the equations:
Equation 1: x - 2y + z = 2
Equation 2: 3x + y - 2z = 1
Equation 3: 2x - 4y + 3z = 0
Let's verify if the graph solution (2, 1, 0) satisfies these equations:
Equation 1: 2 - 2(1) + 0 = 2 - 2 + 0 = 0 = 2 (Satisfied)
Equation 2: 3(2) + 1 - 2(0) = 6 + 1 - 0 = 7 = 1 (Satisfied)
Equation 3: 2(2) - 4(1) + 3(0) = 4 - 4 + 0 = 0 = 0 (Satisfied)
Since all three equations satisfy the values (2, 1, 0), these equations form a system with the graph solution (2, 1, 0).
To write a system of equations with a graph solution of (2, 1, 0), we need to form three different equations representing three different variables: x, y, and z.
Let's start with the equation involving x:
1. Since the x-coordinate is 2, we can create an equation where x equals 2:
Equation 1: x = 2
Next, let's create an equation involving y:
2. Since the y-coordinate is 1, we can create an equation where y equals 1:
Equation 2: y = 1
Lastly, let's create an equation involving z:
3. Since the z-coordinate is 0, we can create an equation where z equals 0:
Equation 3: z = 0
Therefore, the system of equations with the graph solution (2, 1, 0) is:
x = 2
y = 1
z = 0