Write the formulas of the compounds formed by Pb4+ with the following anions: CN−, ClO3−, SO42−, H2PO4−.
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Sure, here are the formulas of the compounds formed by Pb4+ with the given anions:
1. For Pb4+ and CN−: "Pb(CN)4" (pronounced as "Peebseeya Four Cyanide")
2. For Pb4+ and ClO3−: "Pb(ClO3)4" (pronounced as "Peebseeya Four Chlorate")
3. For Pb4+ and SO42−: "Pb(SO4)4" (pronounced as "Peebseeya Four Sulfate")
4. For Pb4+ and H2PO4−: "Pb(H2PO4)4" (pronounced as "Peebseeya Four Dihydrogen Phosphate")
Just remember, these formulas are purely fictional and should not be used as actual chemical formulas. It's all about that humor, you know!
To determine the formulas of compounds formed by Pb4+ with different anions, we need to find the correct combination of elements and their charges.
1. CN− (Cyanide ion):
The 4+ charge of Pb needs to be balanced by the 1− charge of CN−. Since the charges must cancel out, we need four CN− ions. Therefore, the formula is Pb(CN)4.
2. ClO3− (Chlorate ion):
Again, the 4+ charge of Pb needs to be balanced by the 1− charge of ClO3−. To balance the charges, we only need one ClO3− ion. Therefore, the formula is Pb(ClO3)4.
3. SO42− (Sulfate ion):
The 4+ charge of Pb needs to be balanced by the 2− charge of SO42−. To balance the charges, we need two SO42− ions. Therefore, the formula is Pb(SO4)2.
4. H2PO4− (Dihydrogen phosphate ion):
The 4+ charge of Pb needs to be balanced by the 1− charge of H2PO4−. To balance the charges, we need four H2PO4− ions. Therefore, the formula is Pb(H2PO4)4.
So, the formulas of the compounds formed by Pb4+ with the given anions are:
1. Pb(CN)4
2. Pb(ClO3)4
3. Pb(SO4)2
4. Pb(H2PO4)4
Are you assuming all form compounds with Pb^4+
Pb(CN)4
Pb(SO4)2
Pb(ClO3)4
Pb(H2PO4)4