The questions asks to write a word equation and a balanced chemical equation for a reaction between aqueous copper (ii) sulfate and solid iron. Assume that iron forms the Fe2+ ion.) Include proper states of matter after each substance (s, l, g, aq).

Question

The questions asks to write a word equation and a balanced chemical equation for a reaction between aqueous copper (ii) sulfate and solid iron. Assume that iron forms the Fe2+ ion.) Include proper states of matter after each substance (s, l, g, aq).

Here is what I got ANSWER:

Copper (ii) sulfate (aq) + iron (s) --> iron sulfate (aq) + copper

CuSo4 (aq) + Fe (s) --> FeSO4 (aq) + Cu (s)

I'm sure that is right. Now i'm confused on the second part of the question which is...

QUESTION: Assuming 16.83 g of solid iron react with an aqueous solution of copper (ii) sulfate according to the above balanced chemical Equation. Calculate the THEORETICAL YIELD of COPPER produced.

So how do you do this??? I got lost.

Answer 1

For every mole of Fe you used, you get a mole of FeSO4

molesFeSO4=molesFe=16/atomicmassFe

Mass feSO4=molesFeSO4*molmassFeSO4

Answer 2

So the theoretical yield is

16.83 g Fe (s)
____________________________ x 100% =
55.845 atomic mass of Fe

= 30.14

Now what do I do. Is that correct?

***feSO4=molesFeSO4*molmassFeSO4

151.908 g/mol = 1 mol FeSO4 x 151.908 ?
Help please? Thankyou sorry this is long

Answer 3

To calculate the theoretical yield of copper produced, you need to first determine the limiting reactant in the reaction. The limiting reactant is the reactant that is completely consumed in the reaction and determines the maximum amount of product that can be formed.

In this case, we have 16.83 g of solid iron as the limiting reactant. We'll use the balanced chemical equation to calculate the molar ratio between iron and copper in the reaction.

First, we need to convert the mass of iron to moles:

Molar mass of iron (Fe) = 55.845 g/mol
Moles of iron = mass of iron / molar mass of iron = 16.83 g / 55.845 g/mol = 0.3013 mol

From the balanced chemical equation:
1 mol of Fe reacts with 1 mol of Cu (copper)

So, 0.3013 mol of Fe will react with 0.3013 mol of Cu.

Now, we need to find the molar mass of copper (Cu):
Molar mass of copper (Cu) = 63.546 g/mol

To calculate the theoretical yield of copper, we multiply the moles of Cu by its molar mass:

Theoretical yield of Cu = moles of Cu × molar mass of Cu
Theoretical yield of Cu = 0.3013 mol × 63.546 g/mol = 19.11 g

Therefore, the theoretical yield of copper produced in this reaction is 19.11 grams.

Answer 4

To calculate the theoretical yield of copper produced, you need to use stoichiometry and the balanced chemical equation.

First, determine the molar mass of iron (Fe) and copper (Cu) using the periodic table. The molar mass of Fe is 55.85 g/mol and the molar mass of Cu is 63.55 g/mol.

Next, calculate the number of moles of iron (Fe) used in the reaction. Divide the given mass (16.83 g) by the molar mass of iron:

moles of Fe = mass of Fe / molar mass of Fe = 16.83 g / 55.85 g/mol

Now, use the balanced chemical equation to establish the stoichiometric ratio between iron and copper. According to the equation, the ratio of moles of copper produced to moles of iron consumed is 1:1.

Since we know the moles of iron used, the moles of copper produced will be the same:

moles of Cu = moles of Fe = 16.83 g / 55.85 g/mol

Finally, convert the moles of copper to grams by multiplying by the molar mass of copper:

mass of Cu = moles of Cu × molar mass of Cu = 16.83 g / 55.85 g/mol × 63.55 g/mol

By performing the calculation, you will get the theoretical yield of copper produced in grams.