A stone of mass 0.7kg is projected vertically upward with a speed of 5m/s.calculate the maximum height reached. [Take g=10m/s^2 and neglect air resistance].

"

The appropriate formular is..

H=u(square)/2g..
height=U square(initial vel.) /divided by 2g
so,_H=5sqr /2*10.
Therefore;-25 /20..which is equare to 1.25m. ans(1.25 m).

a baseball is thrown vertically upward with an initial speed of 20m/s .calculate how fast it was travelling on its way down when caught 5.0m above where it was thrown.

2.8

Well, well, well, we have a stone trying to break free from the Earth's clutches! You go, little stone! Now, to calculate the maximum height reached, we can use some fantastic physics magic!

First, we need to find the initial velocity when the stone reaches maximum height. Since it's projected upwards, we can say goodbye to gravity pulling it down. That means the final velocity at maximum height is 0 m/s. So, we have our initial velocity of 5 m/s.

Now, we just need to use some fancy kinematics equations to find the maximum height. We can use the good ol' equation:

V_final^2 = V_initial^2 + 2*a*d

Plug in our values:

0 = (5m/s)^2 + 2*(-10m/s^2)*d

Simplify that equation:

0 = 25m^2/s^2 - 20m/s^2*d

Rearrange a bit:

20m/s^2*d = 25m^2/s^2

Divide both sides by 20m/s^2:

d = 25m^2/s^2 / 20m/s^2

d = 1.25m^2

Voila! The maximum height reached by the stone is approximately 1.25 meters. That's one brave stone going higher than I ever could!

To calculate the maximum height reached by the stone, we can use the principles of projectile motion. Here's how you can solve the problem step by step:

1. Identify the relevant variables:
- Mass of the stone (m): 0.7 kg
- Initial velocity (u): 5 m/s (upward)
- Acceleration due to gravity (g): 10 m/s^2 (downward)

2. Determine the maximum height using the formula:
- The formula to calculate the maximum height reached by a projectile is: h = (u^2)/(2g)
- Substituting the given values, we get: h = (5^2)/(2 * 10)

3. Calculate the result:
- Evaluate the expression: h = 25/20
- Simplifying, h = 1.25 meters

Therefore, the maximum height reached by the stone is 1.25 meters.

V^2 = Vo^2 + 2g*h, V = 0, Vo = 5m/s, g = -10m/s^2, h = ?.