A rental truck costs $50 plus $0.40 per mile.

Write an equation that gives the cost of driving the truck x miles
Use the intersection of graphs method to determine the number of miles that the truck is driven if the rental cost is $70.
Solve part (b) numerically with a table of values.
(a) An equation that gives the cost of driving the truck x miles is y=

so, did you graph them?

yes i'm having trouble with chart

To write an equation that gives the cost of driving the truck x miles, we can use the given information that the truck costs $50 plus $0.40 per mile.

Let's break it down:

The fixed cost of the truck rental is $50.
The variable cost is $0.40 per mile.

So, the equation that gives the cost of driving the truck x miles is:
y = 50 + 0.40x

Now let's move on to part (b) and use the intersection of graphs method to determine the number of miles the truck is driven if the rental cost is $70.

To find the intersection point, we need to set the equation y = 70 and solve for x.

70 = 50 + 0.40x

Simplifying the equation, we have:
0.40x = 20

To solve for x, divide both sides of the equation by 0.40:
x = 20/0.40
x = 50

Hence, the truck is driven 50 miles if the rental cost is $70.

For part (c), let's solve it numerically with a table of values. We will find the cost for different values of x and check when it equals $70.

Let's consider values of x from 0 to 100 in increments of 10 and calculate the corresponding cost using the equation y = 50 + 0.40x:

x | y
--------------
0 | 50
10 | 54
20 | 58
30 | 62
40 | 66
50 | 70
60 | 74
70 | 78
80 | 82
90 | 86
100 | 90

From the table, we see that the cost equals $70 when the truck is driven 50 miles, as we previously found using the graph method.

So, both methods yield the same result, confirming that the truck is driven 50 miles if the rental cost is $70.