The sum of two numbers is 19.Five times the lesser number is four more than twice the great.What are the numbers?I'm trying to figure out if my answer is correct.
5(-b+19)=4+2(b)
a+b+19
-b
a=-b+19
5(-b+19)=4+2(b)
-5b+95 =4+2b
-2b -95 -2b
-7b
-7b =-95
-7
=13
a+13=19
-13 -13
a=6
At first I thought your work was a hodgepodge, but further study shows that you are correct.
except that 95/7 is not 13. Should have been 91, so you messed up somewhere.
To check if your answer is correct, let's substitute the values of a and b back into the original equation "The sum of two numbers is 19. Five times the lesser number is four more than twice the greater."
The original equation is:
a + b = 19 (Equation 1)
Now, let's substitute the values of a and b that you found:
a = 6
b = 13
Substituting these values into Equation 1, we get:
6 + 13 = 19
This equation is indeed true. Therefore, your answer is correct. The two numbers that satisfy the given conditions are 6 and 13.