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A block of mass m = 2.00 kg is released from rest h = 0.500 m from the surface of a table, at the top of a theta = 30.0° incline. The frictionless incline is fixed on a table of height H = 2.00 m. (a) Determine the acceleration of the block as it slides down the incline. (b) What is the velocity of the block as it leaves the incline? (c) How far from the table will the block hit the floor? (d) How much time has elapsed between when the block is released and when it hits the floor? (e) Does the mass of the block affect any of the above calculations?

Thank you!!

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2 answers

  1. good but answer with explanation

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  2. a) mgsin30 = ma
    a = 9.8sin30
    b) mgh = 1/2 mv^2
    v = sqrt(2*9.8*.5)
    c) t = sqrt( 2 (2))/9.8)
    x = v (part b) * t (part c)
    d) find time on slide by finding hypontenuse distance and a from part a. Add to time from c
    e) Nope

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