Ms. Sue could you please help me with this question:A rectangular room is 6 meters longer than it is wide, and its perimeter is 28 meters. Find the dimension of the room.
The length is:_____meters and the width is___meters.
P = 2L + 2W
28 = 2(W + 6) + 2W
28 - 2W + 12 + 2W
16 = 4W
? = W
I did this for you when you were Seymour
http://www.jiskha.com/display.cgi?id=1453950266
No Reiny you didn't actually do anything.
I'm sorry you were unable to understand Reiny's very clear explanation.
So ms. Sue I get 4 for the width after i 16/4. How do I find the length? Will it be 6(4)?
The width is 4.
"A rectangular room is 6 meters longer than it is wide, . . ."
So it's 6(4)=24?
I got the width right, but now my question is how do I find the length. Sorry math isn't my favorite subject 😔😔
To find the dimensions of the room, we can set up equations based on the given information.
Let's say the width of the room is 'w' meters. According to the problem, the length of the room is 6 meters longer than the width, so the length would be 'w + 6' meters.
The perimeter of a rectangle can be calculated by adding the lengths of all four sides. In this case, the perimeter is given as 28 meters.
So we can set up the equation:
2(w + w + 6) = 28
Simplifying the equation:
2(2w + 6) = 28
4w + 12 = 28
4w = 28 - 12
4w = 16
w = 16/4
w = 4
Therefore, the width of the room is 4 meters.
The length would be 'w + 6', which is 4 + 6 = 10 meters.
So, the dimensions of the room are:
Length: 10 meters
Width: 4 meters