sum of 3 consecutive integers is 144. what r the integers?
r = first number
r + 1 = second number
r + 2 = third number
r + r + 1 + r + 2 = 144
3 r + 3 = 144 Subtract 3 To both sides
3 r + 3 - 3 = 144 - 3
3 r = 141 Divide both sides by 3
r = 141 / 3 = 47
r + 1 = 48
r + 2 = 49
47 + 48 + 49 = 144
144/3 = ?
Take it from there.
Let's solve this step by step.
1. Let's assume the first integer is x.
2. The next consecutive integer would be x + 1.
3. And the third consecutive integer would be x + 2.
According to the given information:
x + (x + 1) + (x + 2) = 144
Now, let's solve the equation:
3x + 3 = 144
3x = 144 - 3
3x = 141
x = 141 / 3
x = 47
So, the three consecutive integers are:
First integer: 47
Second integer: 48
Third integer: 49
Therefore, the three integers are 47, 48, and 49.
To find the three consecutive integers, we can represent them as x, x+1, and x+2.
According to the problem, the sum of these three consecutive integers is 144. So, we can write the equation as:
x + (x+1) + (x+2) = 144
Simplifying the equation:
3x + 3 = 144
Subtracting 3 from both sides:
3x = 141
Dividing both sides by 3:
x = 47
Therefore, the three consecutive integers are 47, 48, and 49.