The molarity of concentrated HCl purchased for laboratory use is approximately
12.1 M. How many milliliters of this reagent should be diluted to 1.000 L to make
0.100 M HCl?
1 L of .1 M contains .1 moles
volume = .1 mole / 12.1 mol/L
.1 / .0121 mol/ml = ?
Molarity is love
To find the volume of concentrated HCl needed to make a 0.100 M solution, we can use the formula:
M₁V₁ = M₂V₂
Where:
M₁ = molarity of concentrated HCl
V₁ = volume of concentrated HCl
M₂ = desired molarity of HCl
V₂ = final volume of the solution
Given:
M₁ = 12.1 M
M₂ = 0.100 M
V₂ = 1.000 L = 1000 mL
Using the formula, we can solve for V₁:
12.1 M x V₁ = 0.100 M x 1000 mL
V₁ = (0.100 M x 1000 mL) / 12.1 M
V₁ = 8.26 mL (approximately)
Therefore, approximately 8.26 mL of concentrated HCl should be diluted with water to make 1.000 L (1000 mL) of 0.100 M HCl.
To find out how many milliliters of the concentrated HCl reagent should be diluted to 1.000 L to make a 0.100 M HCl solution, we can use the equation:
M1 × V1 = M2 × V2
where:
M1 is the initial molarity of the concentrated HCl solution
V1 is the initial volume of the concentrated HCl solution
M2 is the final desired molarity of the diluted HCl solution
V2 is the final desired volume of the diluted HCl solution
Plugging in the given values:
M1 = 12.1 M
V1 = ?
M2 = 0.100 M
V2 = 1.000 L
Rearranging the equation, we get:
V1 = (M2 × V2) / M1
Plugging in the values:
V1 = (0.100 M × 1.000 L) / 12.1 M
Simplifying the equation gives us:
V1 = 0.00826 L
To convert liters to milliliters, we multiply by 1000:
V1 = 0.00826 L × 1000 mL/L
Calculating the result, we get:
V1 = 8.26 mL
Therefore, approximately 8.26 milliliters of the concentrated HCl reagent should be diluted to 1.000 L to make a 0.100 M HCl solution.