A hand bag containing some loads weighing 162n is carried by two student,
each holding the handle of the bag next to him..if each handle is pulled 60degree to the vertical
find the force of each student?
Help plz
up force from each student = 81 N
= F cos 60 = F/2
so
162 N
How to solution this question
Pls how do u get F cos60?
Well, here's a little math joke for you:
Why did the math book look sad?
Because it had too many problems!
But don't worry, I'm here to help you with yours. Let's solve this problem together!
Since the bag is being carried by two students holding the handles next to them, we can assume that the weight is evenly distributed between them.
To find the force of each student, we'll use a little trigonometry. Since each handle is pulled 60 degrees to the vertical, we can use the sine function:
sin(60) = opposite/hypotenuse
In this case, the hypotenuse is the force exerted by each student, and the opposite side is the weight of the bag. So we have:
sin(60) = 162N / F
Simplifying the equation, we get:
F = 162N / sin(60)
Now we can plug in the values:
F = 162N / 0.866
Calculating this, we find that the force exerted by each student is approximately 187N.
So, each student needs to exert a force of about 187 Newtons to carry the bag. But remember, this is just an approximate value, so be careful not to strain yourself in real life situations!
To find the force of each student, we can break down the problem into components. Let's assume that the total force required to hold the bag is evenly distributed between the two students.
First, we need to find the vertical component of the force. Since the bag is being pulled at an angle of 60 degrees to the vertical, the vertical component can be calculated using the formula:
Force_vertical = Force_total * cos(angle)
Here, the Force_total is the total force required to hold the bag (162 N in this case), and the angle is the angle the handle makes with the vertical (60 degrees).
So, Force_vertical = 162 N * cos(60 degrees)
Next, we need to find the horizontal component of the force. The horizontal component can be calculated using the formula:
Force_horizontal = Force_total * sin(angle)
Using the same values as above, we have:
Force_horizontal = 162 N * sin(60 degrees)
Now, we have the vertical and horizontal components of the force exerted by each student.
Therefore, the force exerted by each student is:
Vertical component = Force_vertical = 162 N * cos(60 degrees)
Horizontal component = Force_horizontal = 162 N * sin(60 degrees)
By evaluating these equations, we can find the specific numerical values for each component of the force exerted by each student.