Every two-digit number whose units digit is three times its tens digits

39

26
13

well what are the choices for tens digit

1 ---> 3
2 ---> 6
3 ---> 9
and bigger will not work so
13
26
39

Well, it sounds like you're looking for a little number humor! You're in luck, because I've got just the answer for you. Let's find those quirky two-digit numbers where the units digit is three times the tens digit.

First, let's assume that the tens digit is "x." That means the units digit should be three times x, so it's 3x. So our two-digit number would be 10x + 3x, which simplifies to 13x.

Now, we want to find when 13x is a two-digit number. Since x needs to be a single-digit number (0-9), let's check what happens when we plug in some values:

When x is 1, 13x is 13, which is a two-digit number.
When x is 2, 13x is 26, still a two-digit number.
When x is 3, 13x is 39, and it's still a two-digit number.
And so on... you'll find that when x is any digit from 1 to 7, you'll get a two-digit number.

But when x is 8 or 9, 13x will be more than 100, so it won't be a two-digit number anymore.

So, the two-digit numbers that fit this pattern are 13, 26, 39, 52, 65, and 78. These are the answers to your question, my friend!

Remember, when it comes to numbers, there's always a funny side!

To find every two-digit number whose units digit is three times its tens digit, we need to consider all possible combinations of tens and units digits.

First, let's assign variables for the tens and units digits:
Let the tens digit be represented by the variable 't'
Let the units digit be represented by the variable 'u'

According to the given condition, the units digit is three times the tens digit. We can express this as the equation:
u = 3t

Since the tens digit can range from 0 to 9, we can iterate through each possible value and calculate the corresponding units digit.

Let's go through the values of t and calculate the units digit for each case:

For t = 0, u = 3 * 0 = 0. Thus, the two-digit number is 0.

For t = 1, u = 3 * 1 = 3. So, the two-digit number is 13.

For t = 2, u = 3 * 2 = 6. The two-digit number is 26.

For t = 3, u = 3 * 3 = 9. Therefore, the two-digit number is 39.

For t = 4, u = 3 * 4 = 12. However, since we are looking for a two-digit number, we exclude this case.

Following the same logic, for t = 5 to 9, there are no two-digit numbers that satisfy this condition because the units digit becomes greater than 9.

Therefore, the only two-digit numbers that satisfy the condition are 13, 26, and 39.

In short, the two-digit numbers whose units digit is three times its tens digit are 13, 26, and 39.