please balance this chemical equation iron +oxygen > iron (III) oxide +energy
Fe + O2> Fe2 O3 + heat and light
4Fe + 3O2> 2Fe2O3 + heat and light
Fe2+O3
The given chemical equation is:
Fe + O2 > Fe2O3 + energy
To balance the chemical equation, we need an equal number of atoms on both sides of the equation. Let's start by balancing the iron atoms:
On the left side of the equation, we have 1 iron (Fe) atom.
On the right side, we have 2 iron (Fe) atoms in Fe2O3.
To balance the iron atoms, we need to put a coefficient of 2 in front of Fe:
2Fe + O2 > Fe2O3 + energy
Next, let's balance the oxygen atoms:
On the left side, we have 2 oxygen (O) atoms in O2.
On the right side, we have 3 oxygen (O) atoms in Fe2O3.
To balance the oxygen atoms, we need to put a coefficient of 3/2 or 1.5 in front of O2. However, we can't have a fractional coefficient in a balanced chemical equation.
To avoid the fractional coefficient, we can multiply each coefficient by 2:
4Fe + 3O2 > 2Fe2O3 + energy
Finally, the equation is balanced with 4 iron (Fe) atoms, 6 oxygen (O) atoms, and equal numbers of atoms on both sides:
4Fe + 3O2 > 2Fe2O3 + energy