Hello. My algebra teacher gave me this worksheet last week and everyone had to bring it yesterday and I haven't done it yet. Can someone please help me. He said Friday is the last day or he's going to take away some points. I've been having trouble with all these math problems. I feel like the class is moving to fast and i'm just there. My mom does try to help me but she always yells and gets mad at me when i don't understand so I just decided its better of to just study alone. I'm going to start with my new tutor next week and i'm going to write these questions and let her explain to me but for right now I really need these answers. Please please don't say i'm lasy becuase i'm really not i'm just a bit slow when it comes to math. Thanks to who ever answers in advance.

1.Determine whether the equation represents a direct variation. If it does, find the constand of variation. 2y= 5x + 1

Not a direct variation
Direct variation, constant of variation is 5/2
Direct variation, constant variation is 2/5
Direct variation, constand of variation is 1-2/5

2. Determine whether the equation represents a direct variation. If it does, find the constant of variation.
-12x=6y

Not a direct variation
Direct variation, constant of variation is 1/2
Direct variation, constant variation is 2
Direct variation, constand of variation is -2

3. Determine whether the equation represents a direct variation. If it does, find the constant of variation.

0.7x-1.4y=0

Not a direct variation
Direct variation, constant of variation is 1/2
Direct variation, constant variation is 2
Direct variation, constand of variation is -2

4. Suppose y varies directly with x. Write a direct variation equation that relates x and y.
y= -10 when x=2

y= -5x
y= -1/5x
y=5x
y=1/5x

5.Suppose y varies directly with x. Write a direct variation equation that relates x and y.

y=10.4 when x =4

y= 3.4x
y=3.8x
y=3.2x
y=2.6x

6. Suppose y varies directly with x. Write a direct variation equation that relates x and y.
y= 7 1/2 when x =3

y= 3/2x
y= 2/3x
y=5/2x
y=2/5x

7. graph the direct variation equation.
y= 1/3x

8.graph the direct variation equation.
y= -1/2x

9. For the data in the table, tell whether y varies directly with x. if it does, write an equation for the first direct variation.
x y
3 5.4
7 12.6
12 21.6

Not a direct variation
Direct variation, y= 1.8x
Direct variation, y= 4x
Direct variation, y= 5/9x

10.For the data in the table, tell whether y varies directly with x. if it does, write an equation for the first direct variation.

x y
-2 1
3 6
8 11

well the answers are

1 A
2 D
3 c
4 A
5 C
6 D
7 A
8 C
9 B
10 A
thank you @Reiny

The whole assignment seems to deal only with one simple concept, a direct variation

Sometimes text or your notes have definitions that are difficult to understand.
Here is the definition that is easy to understand:
A direct variation gives you an equation that contains no constants, and there are no exponents on the two variables.

e.g. y = 8x is a direct variation,
but y = 8x + 4 is NOT, since I see a constant of 4

a direct variation can be written in the form
y = kx , where k is the constant of variation

#1, not a variation, I see a +1 sitting there as a constant
#2, yes it is a direct variation:
-12x = 6y
6y = -12x
y = -2x
so the constant of variation is -2 , if y varies directly with x
or
-12x = 6y
x = -(1/2)x
now the constant of variation is -1/2 , if x varies directly as y
so it depends how you express the equation, either in terms of x or in terms of y

#3,
.7x - 1.4y = 0
.7x = 1.4y
1.4y = .7x
y = (.7/1.4)x = (1/2)x
so , yes it is, and the constant of variation is 1/2

From #4 on, you have to first find the equation.
I will do #4, you try the remaining.

#4, they tell us it is a direct variation, so it must look like
y = kx
They give us x=2 when y = -10
let's plug in those values:
-10 = k(2)
2k = -10
k = -5
aaahhhh, so y = -5x is our equation

#6, same way, just some fractions to deal with

#7, to graph, pick any x, and find the y to get ordered pairs,
e.g. let x = 3, then y = (1/3)(3) = 1, --> point(3,1)
let x = 9, then y = (1/3)(9) = 3 ---> point (9,3)
plot those two points, and join with a straight line

Notice how I picked multiple of 3's for my x's so I could take 1/3 of the x without ending up with fractions?

#8 , same as #7, pick multiples of 2 for your x's

#9 and #10 are the same type
#9
assume it is a direct variation, then its equation must be
y = kx
use the first given data: x = 3, y = 5.4
then 5.4 = k(3)
3k = 4.5
k = 1.5
equation is y = 1.5x
do the other points satisfy our equation?
for (7, 12.6)
is 12.6 = 1.5(7) ?
12.6 = 10.5 ??? NO, so the given data is NOT a direct variation

#10 same way

TBH all right but 3 cuase 3 is B

1. A

2. D
3. B
4. A
5. C
6. D
7. A
8. C
9. B
10. A

For connexus Unit 6 Lesson 2 practice:

1. A (Not a direct variation)
2. D (direct, -2)
3. B (direct, 1/2)
4. A (y= -5x)
5. C (5/2x)
6. D (y= 2.6x)
7. A
8. C
9. B (Direct, 1.8x)
10. Not a direct variation
Hope this helped :)

3 is b

@tbh and @Reiny are right! Those are the correct answers.

man I feel ya, whenever my mom tries to help me with algebra she yells at me when I don't understand

tbh is right, except for 3. The answer to 3 is b.

still right in 2017 100% with 3 as B. and yeah this is a connexus practice which counts for 0% of your overall grade, lol.