The length of a rectangle is 5 inches less than 3 times the width. The perimeter of the rectangle is 14 inches. Find the length and width of the rectangle.
I did this: Length 3x-5; width 3x
Then I did guess and check and came up with X=2 solving the problem with a perimeter of 14. But, the answer is supposed to be length 4inches, width 3inches.
Please explain what I did wrong. I know the answer but not how to get it.
P = 2L + 2W
14 = 2(3W - 5) + 2W
14 = 8W - 10
24 = 8W
3 = W
Ok, I get it now. Thank you.
:-)
You're welcome.
ok say if the hight is 6in and the length is 10 and it = 240 is the volume then what is the width
To solve this problem correctly, you need to use algebraic equations. Let's break down the steps to find the correct solution:
1. Assign variables: Let's use "L" for length and "W" for width.
2. Translate the problem into equations:
- The length is 5 inches less than 3 times the width: L = 3W - 5
- The perimeter of a rectangle is found by adding up all four sides: Perimeter = 2L + 2W
3. Substitute the equation for length (L) into the equation for perimeter:
14 = 2(3W - 5) + 2W
4. Simplify and solve for W:
14 = 6W - 10 + 2W
14 + 10 = 8W
24 = 8W
W = 24/8
W = 3 inches
5. Substitute the value of W into the equation for length (L):
L = 3W - 5
L = 3(3) - 5
L = 4 inches
Therefore, the correct solution is length = 4 inches and width = 3 inches. By using algebra, we can find the accurate answer instead of relying on guess and check methods.