Find the length of a segment that has endpoints h(2, -3) and j(12, 7)
20
10 square root 2
4 square root 2
40
Please help? Thx
C
B
D
A
B
hj = √( (12-2)^2 + (-3-7)^2 )
= √(100 + 100)
= √200
= 10√2
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To find the length of a segment with endpoints (h₁, h₂) and (j₁, j₂), you can use the distance formula. The formula is:
d = √((j₁ - h₁)² + (j₂ - h₂)²)
Using the given endpoints h(2, -3) and j(12, 7), we can substitute these values into the formula:
d = √((12 - 2)² + (7 - (-3))²)
= √(10² + 10²)
= √(100 + 100)
= √(200)
= 10√2
Therefore, the length of the segment with endpoints h(2, -3) and j(12, 7) is 10√2. So the answer is:
10√2