A painter is to mix green and yellow paint in the ratio of 4 to 7 to obtain the color she wants. If she has 28 liters of green paint, how many liters of yellow paint should be added?
I need to know what algebraic equation I need to use...I believe this is a proportion type question....
let the amount of yellow paint be y L
then 28/y = 4/7
4y = 196
y = 49
notice 28:49 = 4:7
The answer is 49
Well, dear painter, let's take a colorful journey into the world of algebra! To find the number of liters of yellow paint needed, we'll set up a proportion using the ratio of green to yellow paint.
Let's call the number of liters of yellow paint needed "y." According to the ratio, the amount of green paint is 28 liters. So our proportion will be:
4/7 = 28/y
To solve for y, we can cross-multiply:
4y = 7 * 28
Now, don't worry about doing the math, I'm here to help! Multiplying 7 by 28 gives us 196, so:
4y = 196
To find y, we just need to divide both sides of the equation by 4:
y = 196/4
And when you simplify that, you'll find that you need 49 liters of yellow paint to achieve your desired color. Happy mixing, my artistic friend!
To solve this problem, you can set up a proportion since the painter wants to mix green and yellow paint in a specific ratio.
Let's assume the unknown quantity of yellow paint is represented by "y" liters.
Based on the given information, the ratio of green paint (G) to yellow paint (Y) is 4:7, which can be written as:
G/Y = 4/7
Substituting the value given for the green paint, which is 28 liters, the equation becomes:
28/Y = 4/7
To solve this equation, you can use cross-multiplication. Multiply the numerator of the first fraction (28) with the denominator of the second fraction (7), and the numerator of the second fraction (4) with the denominator of the first fraction (Y):
28 * 7 = 4 * Y
Simplifying, we have:
196 = 4Y
To solve for Y, divide both sides of the equation by 4:
196/4 = Y
Simplifying further, we find:
49 = Y
Therefore, the painter would need to add 49 liters of yellow paint to obtain the desired color.