In many residential water systems, the aqueous Fe3+ concentration is high enough to stain sinks and turn drinking water light brown. The iron content is analyzed by first reducing the Fe3+ to Fe2+ and then titrating with MnO4- in acidic solution.
Fe2+(aq) + MnO4-(aq) ? Mn2+(aq) + Fe3+(aq)
Balance the skeleton reaction of the titration step. (Use the lowest possible coefficients. Include states-of-matter under SATP conditions in your answer.)
In the process of titration iron gets reduced and Mn gets oxidized in presence of acidic condition.
Now if we write redox half cell equation for both the process we got,
Fe3= ---- Fe2+ + e ............. 1st redox equation where it is reduced
MnO-4 + H+ ---- Mn2+ + H2O ...............2nd redox equation where it is oxidized
now from 2nd redox equation we can balance both side to get balanced no of oxygen and hydrogen as per rule of balancing
MnO-4 + H+ -------- Mn+2 + H2O
MnO-4 + 8H+ -------- Mn+2 + 4H2O
Now to balance electrons in both the side
MnO-4 + 8H+ + 5e -------- Mn+2 + 4H2O................3rd redox equation
now by adding both 3rd and 1st redox equation we got
MnO-4 + 8H+ + 5e + Fe+3 -------- Mn+2 + 4H2O..+ Fe
hence to balance both side electrons finally we got the equation as
MnO4- + 8H+ + 5Fe2+ + 5e- -> Mn2+ + 4H2O + 5Fe3+ + 5e-
Canceling out the electrons:
MnO4- + 8H+ + 5Fe2+ -> Mn2+ + 4H2O + 5Fe3+
and this is the balanced redox equation for the above reaction . Right? thank you.
I can't tell the difference between the question and what I assume is your answer.The skeleton equation is simply
5Fe^2+ + MnO4^- ==> 5Fe^3+ + Mn^2+ and you can add the states.
Most of the rest of what you wrote is not right but the final equation you came up with is correct.
All of that explanation about Fe being reduced and Mn being oxidized is rubbish which I've copied here as
"In the process of titration iron gets reduced and Mn gets oxidized in presence of acidic condition."
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