Ask questions and get helpful answers.

Two numbers are such that twice the greater number exceeds twice the smaller one by 18 and 1/3 of the smaller and 1/5 of the greater numbers are together 21.The numbers are:

  1. 👍
  2. 👎
  3. 👁
  4. ℹ️
  5. 🚩
5 answers
  1. Let the numbers be x and y, with x < y

    2y = 2x+18
    x/3 + y/5 = 21

    Now just solve as usual.

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  2. x = 36
    y = 45

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  3. Full qstion slve ksa o ga

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  4. Let greater number is 'x'
    Smaller number be 'y
    Given,greater number exceeds twice the smaller i.e 2x-2y=18...........1
    1/3 of smaller and 1/5 of greater i.e 1/3×y+1/5×x=21 this is convert as 3x+5y=315......2
    By solving 1 and 2 we get x=45 and y=36
    I hope it will help u ☺️

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  5. Sorry to say but this was not helpful... Because this answer is not with full explanation so it was very difficult to understand

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩

Answer this Question

Related Questions

Still need help?

You can ask a new question or browse existing questions.