Calculate the molarity of a solution prepared by dissolving 10.0 grams of NaOH and then diluting the solution to 500mL.

10.0gNaOH x (1moleNaOH / 39.99711gNaOH) = .250moleHaOH

.250moleNaOH / .500L = .500M

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The molarity of urea in a solution prepared by dissolving 16 g of urea (MW = 60.0 g/mol) in 39g of H2O is M. The density of the .solution is 1.3 g/mL 0.11 .a O 6.3 .b O 3.7 .C O 6.8 .d o 0.16 .e O

To calculate the molarity of the solution, we need to know the number of moles of NaOH and the volume of the solution.

Step 1: Calculate the moles of NaOH using its molar mass.
The molar mass of NaOH is:
Na = 22.99 g/mol
O = 16.00 g/mol
H = 1.01 g/mol

So, molar mass of NaOH = (22.99 + 16.00 + 1.01) g/mol = 40.00 g/mol

Moles of NaOH = 10.0 g / 40.00 g/mol = 0.250 mol

Step 2: Calculate the volume of the solution.
The given volume is 500 mL, which is equivalent to 0.500 L.

Step 3: Calculate the molarity of the solution.
Molarity (M) = Moles of solute / Volume of solution (in liters)

Molarity = 0.250 mol / 0.500 L = 0.500 M

Therefore, the molarity of the solution is 0.500 M.

To calculate the molarity of a solution, we need to know two things: the amount of solute in moles and the volume of the solution in liters.

First, let's find the amount of NaOH in moles:

Step 1: Convert the given mass of NaOH to moles using its molar mass.
The molar mass of NaOH is:
Na (sodium) = 22.99 g/mol
O (oxygen) = 16.00 g/mol
H (hydrogen) = 1.01 g/mol
Total molar mass of NaOH = 22.99 + 16.00 + 1.01 = 40.00 g/mol

To convert grams to moles, divide the given mass by the molar mass:
10.0 grams NaOH * (1 mol NaOH / 40.00 grams NaOH) = 0.25 mol NaOH

Now, let's find the volume of the solution in liters:

Step 2: Convert the given volume (500 mL) to liters.
Since 1 liter (L) = 1000 milliliters (mL),
500 mL * (1 L / 1000 mL) = 0.5 L

Finally, let's calculate the molarity:

Step 3: Divide the moles of solute by the liters of solution:
Molarity (M) = moles of solute (NaOH) / liters of solution

Molarity (M) = 0.25 mol NaOH / 0.5 L = 0.50 M

Therefore, the molarity of the solution prepared by dissolving 10.0 grams of NaOH and diluting it to 500 mL is 0.50 M.