Calculate the molarity of a solution prepared by dissolving 10.0 grams of NaOH and then diluting the solution to 500mL.
10.0gNaOH x (1moleNaOH / 39.99711gNaOH) = .250moleHaOH
.250moleNaOH / .500L = .500M
Is this right?
The molarity of urea in a solution prepared by dissolving 16 g of urea (MW = 60.0 g/mol) in 39g of H2O is M. The density of the .solution is 1.3 g/mL 0.11 .a O 6.3 .b O 3.7 .C O 6.8 .d o 0.16 .e O
To calculate the molarity of the solution, we need to know the number of moles of NaOH and the volume of the solution.
Step 1: Calculate the moles of NaOH using its molar mass.
The molar mass of NaOH is:
Na = 22.99 g/mol
O = 16.00 g/mol
H = 1.01 g/mol
So, molar mass of NaOH = (22.99 + 16.00 + 1.01) g/mol = 40.00 g/mol
Moles of NaOH = 10.0 g / 40.00 g/mol = 0.250 mol
Step 2: Calculate the volume of the solution.
The given volume is 500 mL, which is equivalent to 0.500 L.
Step 3: Calculate the molarity of the solution.
Molarity (M) = Moles of solute / Volume of solution (in liters)
Molarity = 0.250 mol / 0.500 L = 0.500 M
Therefore, the molarity of the solution is 0.500 M.
To calculate the molarity of a solution, we need to know two things: the amount of solute in moles and the volume of the solution in liters.
First, let's find the amount of NaOH in moles:
Step 1: Convert the given mass of NaOH to moles using its molar mass.
The molar mass of NaOH is:
Na (sodium) = 22.99 g/mol
O (oxygen) = 16.00 g/mol
H (hydrogen) = 1.01 g/mol
Total molar mass of NaOH = 22.99 + 16.00 + 1.01 = 40.00 g/mol
To convert grams to moles, divide the given mass by the molar mass:
10.0 grams NaOH * (1 mol NaOH / 40.00 grams NaOH) = 0.25 mol NaOH
Now, let's find the volume of the solution in liters:
Step 2: Convert the given volume (500 mL) to liters.
Since 1 liter (L) = 1000 milliliters (mL),
500 mL * (1 L / 1000 mL) = 0.5 L
Finally, let's calculate the molarity:
Step 3: Divide the moles of solute by the liters of solution:
Molarity (M) = moles of solute (NaOH) / liters of solution
Molarity (M) = 0.25 mol NaOH / 0.5 L = 0.50 M
Therefore, the molarity of the solution prepared by dissolving 10.0 grams of NaOH and diluting it to 500 mL is 0.50 M.