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How much pure calcium carbonate (100.09 g/mol) is required to produce 40.0 mL carbon dioxide gas according to the reaction used in this experiment?

Your unknown will contain between 25-100% calcium carbonate. Answer to 3 significant figures. Do not include the unit, g.

Hint: ( 0.0400 L CO2 ) X ( 1 mol CO2 / 22.4 L ) X ( __ mol CaCO3 / __ mol CO2 ) X ( __ g CaCO3 / 1 mol CaCO3 )

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1 answer
  1. 0.178

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