A rectangular field is four times as long as it is wide. If the perimeter of the field is 400 yards, what are the fields dimensions?
The width of the rectangular field is ____ yards.
L=4W
P=400=2L+2W=10W
W=40, L=160
A farmer has a rectangular field with an area of 3/4 square mile .The field is 1/2 mule wide.
what is the length of the field?
A farmer has a rectangular field with an area of 3/4 square mile .The field is 1/2 mule wide.
what is the length of the field in mile?
:/ dumb as heck
Dumb
D//umb
To find the dimensions of the rectangular field, we can use algebraic equations and solve them to get the answer.
Let's assume that the width of the rectangular field is represented by the variable "w".
According to the problem, the length of the rectangular field is four times as long as it is wide. Therefore, the length would be 4w.
The perimeter of a rectangle is the sum of all its sides. For a rectangle, this can be calculated as:
Perimeter = 2 * (Length + Width)
Substituting the values from the problem, we have:
400 = 2 * (4w + w)
To solve this equation, we first distribute the 2 into the parentheses:
400 = 2 * 5w
Then, we simplify the equation:
400 = 10w
Finally, we divide both sides by 10 to isolate the variable:
40 = w
So, the width of the rectangular field is 40 yards.
To find the length, we can substitute the width back into the equation for the length:
Length = 4w = 4 * 40 = 160 yards.
Therefore, the width of the rectangular field is 40 yards and the length is 160 yards.