I know you use a Pythagorean Identity, sin^2t + cos^2t=1
I got 64/289 for the first one for example and it was wrong.
Your terminology is awful
cot - 8/17 is meaningless
I will assume you were given cot Ø = -8/17 and are asked to find the remaining 5 trig ratios
if cot Ø = -8/17, then tan Ø = -17/8
you should also have memorized the 3 main trig functions in terms of x, y, and r
e.g. tan Ø = y/x = -17/8 ---> terminal point (8, -17)
tan Ø = y/x = 17/-8 ----> terminal point (-8,17)
From the CAST rule we know that Ø must be either in quadrants II or IV , as seen from the position of the terminal arm points.
so make appropriate sketches showing right-angled triangles .
x^2 + y^2 = r^2 , taking one of the points
r^2 = 8^2 + (-17)^2
r^2 = 353
r = √353 , (r is always positive)
sinØ = y/r = 17/√353 or sinØ = 17/√353
cosØ = ±8/√353 so
secØ = ± √353/8
etc using the basic definitions.
Let me know if my assumption was not correct
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