What mass of liquid water at room temperature

(25◦C) can be raised to its boiling point
with the addition of 43.0 kJ of energy?
Answer in units of g.

Q=mcΔT

m=Q/cΔT
m=43000/(4.814)(100-25)

To find the mass of liquid water that can be raised to its boiling point with the addition of 43.0 kJ of energy, we can use the specific heat capacity of water and the equation:

q = m * C * ΔT

Where:
q = heat energy (in joules)
m = mass of water (in grams)
C = specific heat capacity of water (in joules per gram degree Celsius)
ΔT = change in temperature

To simplify the calculation, we can assume that the specific heat capacity of water is constant at 4.18 J/g°C.

The change in temperature can be calculated as:

ΔT = boiling point - initial temperature

The boiling point of water is 100°C, and the initial temperature is 25°C.

ΔT = 100°C - 25°C = 75°C

Now, let's substitute the values into the equation and solve for the mass of water:

43.0 kJ = m * 4.18 J/g°C * 75°C

First, convert 43.0 kJ to J:

43.0 kJ * 1000 J/kJ = 43,000 J

Now, rearrange the equation to solve for mass:

m = 43,000 J / (4.18 J/g°C * 75°C)

m ≈ 165.07 g

Therefore, the mass of liquid water that can be raised to its boiling point with the addition of 43.0 kJ of energy is approximately 165.07 grams.

To determine the mass of liquid water that can be raised to its boiling point with the given amount of energy, we need to use the specific heat capacity of water and the heat equation:

q = m * c * ΔT

Where:
q = amount of heat energy (in joules)
m = mass of water (in grams)
c = specific heat capacity of water (4.18 J/(g°C))
ΔT = change in temperature (in °C)

In this case, we want to find the mass m, so we rearrange the equation to solve for it:

m = q / (c * ΔT)

Given:
q = 43.0 kJ = 43,000 J (since 1 kJ = 1000 J)
c = 4.18 J/(g°C)
ΔT = boiling point - initial temperature = 100°C - 25°C = 75°C

Substituting these values into the equation:

m = 43,000 J / (4.18 J/(g°C) * 75°C)

Simplifying:

m = 43,000 J / (313.5 J/(g)) ≈ 137.192 g

Therefore, approximately 137.192 grams of liquid water at room temperature can be raised to its boiling point with the addition of 43.0 kJ of energy.