An unknown compound contains only C, H, and O. Combustion of 4.40 g of this compound produced 10.4 g of CO2 and 2.83 g of H2O.

figure the mass of carbon in 10.4g CO3

figure the mass of H2 in 2.83g H2O

so in the original molecules
CxHyOz you know the mass of Cx, how many moles is that?
you know the mass of Hy, how many moles is that?

you know now the mole ratio of C:H in the original compound.
It is not possible to find the subscript of O in the compound.

To determine the empirical formula of the unknown compound, we need to find the ratio of carbon, hydrogen, and oxygen atoms in the compound.

Let's start by calculating the moles of CO2 produced:

Molar mass of CO2 = 12.01 g/mol (atomic mass of carbon) + 2 * 16.00 g/mol (atomic mass of oxygen) = 44.01 g/mol

Moles of CO2 = mass of CO2 / molar mass of CO2 = 10.4 g / 44.01 g/mol = 0.236 mol

From the balanced chemical equation of combustion, we know that the molar ratio between CO2 and carbon is 1:1. Therefore, the moles of carbon in the compound is also 0.236 mol.

Next, let's calculate the moles of H2O produced:

Molar mass of H2O = 2 * 1.01 g/mol (atomic mass of hydrogen) + 16.00 g/mol (atomic mass of oxygen) = 18.02 g/mol

Moles of H2O = mass of H2O / molar mass of H2O = 2.83 g / 18.02 g/mol = 0.157 mol

Again, from the balanced chemical equation, we know that the molar ratio between H2O and hydrogen is 2:2 (or 1:1). Therefore, the moles of hydrogen in the compound are also 0.157 mol.

To find the moles of oxygen in the compound, we can use the difference between the total moles and the sum of carbon and hydrogen moles:

Moles of oxygen = Total moles - Moles of carbon - Moles of hydrogen
= 0.236 mol - 0.236 mol - 0.157 mol
= -0.157 mol

The negative result implies that there is an error in the experimental data provided, as we cannot have a negative amount of moles. It's likely that the mass of the given compound is incorrect or there was an error in the measurements.

Without accurate information about the moles of oxygen, we cannot determine the empirical formula of the unknown compound.

To determine the molecular formula of the unknown compound, we need to analyze the information provided.

First, we need to calculate the number of moles of CO2 produced. The molar mass of CO2 is 44.01 g/mol.

Number of moles of CO2 = mass of CO2 / molar mass of CO2

Number of moles of CO2 = 10.4 g / 44.01 g/mol ≈ 0.2361 mol

Next, we need to calculate the number of moles of H2O produced. The molar mass of H2O is 18.02 g/mol.

Number of moles of H2O = mass of H2O / molar mass of H2O

Number of moles of H2O = 2.83 g / 18.02 g/mol ≈ 0.157 mol

Now, let's calculate the number of moles of carbon and hydrogen in the unknown compound.

Number of moles of carbon = 0.2361 mol (since 1 mol of CO2 contains 1 mol of carbon)

Number of moles of hydrogen = 2 * 0.157 mol (since 1 mol of H2O contains 2 mol of hydrogen)

Number of moles of hydrogen = 0.314 mol

To find the number of moles of oxygen, we need to consider that the unknown compound contains only carbon, hydrogen, and oxygen, and the total number of moles should add up to the total number of moles found in CO2 and H2O.

Total number of moles = Number of moles of carbon + Number of moles of hydrogen + Number of moles of oxygen

Total number of moles = 0.2361 mol + 0.314 mol + Number of moles of oxygen

Since we know that the total number of moles is equal to 4.40 g divided by the molar mass of the compound, which we are trying to find, we can set up the following equation:

4.40 g / molar mass of the compound = 0.2361 mol + 0.314 mol + Number of moles of oxygen

Now, we can rearrange the equation to solve for the molar mass of the compound:

Molar mass of the compound = 4.40 g / (0.2361 mol + 0.314 mol + Number of moles of oxygen)

Molar mass of the compound = 4.40 g / (0.5501 mol + Number of moles of oxygen)

However, we don't have enough information to directly calculate the molar mass of the compound because we don't know the number of moles of oxygen. To determine the molecular formula, we need the molar mass of the compound.

If you have additional information, such as the percent composition of the compound or any other data, please provide it, and I can help you further.